-5(3-2H)-2[4H-2(1+H)]-4=0

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Solution for -5(3-2H)-2[4H-2(1+H)]-4=0 equation: 


Simplifying
-5(3 + -2H) + -2[4H + -2(1 + H)] + -4 = 0
(3 * -5 + -2H * -5) + -2[4H + -2(1 + H)] + -4 = 0
(-15 + 10H) + -2[4H + -2(1 + H)] + -4 = 0
-15 + 10H + -2[4H + (1 * -2 + H * -2)] + -4 = 0
-15 + 10H + -2[4H + (-2 + -2H)] + -4 = 0

Reorder the terms:
-15 + 10H + -2[-2 + 4H + -2H] + -4 = 0

Combine like terms: 4H + -2H = 2H
-15 + 10H + -2[-2 + 2H] + -4 = 0
-15 + 10H + [-2 * -2 + 2H * -2] + -4 = 0
-15 + 10H + [4 + -4H] + -4 = 0

Reorder the terms:
-15 + 4 + -4 + 10H + -4H = 0

Combine like terms: -15 + 4 = -11
-11 + -4 + 10H + -4H = 0

Combine like terms: -11 + -4 = -15
-15 + 10H + -4H = 0

Combine like terms: 10H + -4H = 6H
-15 + 6H = 0

Solving
-15 + 6H = 0

Solving for variable 'H'.

Move all terms containing H to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 6H = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 6H = 0 + 15
6H = 0 + 15

Combine like terms: 0 + 15 = 15
6H = 15

Divide each side by '6'.
H = 2.5

Simplifying
H = 2.5

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